Distance from Simpelveld to Secaucus
The shortest distance (air line) between Simpelveld and Secaucus is 3,724.84 mi (5,994.55 km).
How far is Simpelveld from Secaucus
Simpelveld is located in Zuid-Limburg, Netherlands within 50° 49' 59.88" N 5° 58' 59.88" E (50.8333, 5.9833) coordinates. The local time in Simpelveld is 15:47 (24.12.2025)
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 09:47 (24.12.2025)
The calculated flying distance from Secaucus to Secaucus is 3,724.84 miles which is equal to 5,994.55 km.
Simpelveld, Zuid-Limburg, Netherlands
Related Distances from Simpelveld
Secaucus, New Jersey, United States