Distance from Sint Anthonis to Celakovice
The shortest distance (air line) between Sint Anthonis and Celakovice is 399.28 mi (642.58 km).
How far is Sint Anthonis from Celakovice
Sint Anthonis is located in Noordoost-Noord-Brabant, Netherlands within 51° 37' 32.88" N 5° 52' 51.96" E (51.6258, 5.8811) coordinates. The local time in Sint Anthonis is 16:31 (21.04.2025)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 16:31 (21.04.2025)
The calculated flying distance from Celakovice to Celakovice is 399.28 miles which is equal to 642.58 km.
Sint Anthonis, Noordoost-Noord-Brabant, Netherlands
Related Distances from Sint Anthonis
Celakovice, Středočeský kraj, Czechia