Distance from Sint Anthonis to Cesky Tesin
The shortest distance (air line) between Sint Anthonis and Cesky Tesin is 572.03 mi (920.59 km).
How far is Sint Anthonis from Cesky Tesin
Sint Anthonis is located in Noordoost-Noord-Brabant, Netherlands within 51° 37' 32.88" N 5° 52' 51.96" E (51.6258, 5.8811) coordinates. The local time in Sint Anthonis is 06:23 (22.04.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 06:23 (22.04.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 572.03 miles which is equal to 920.59 km.
Sint Anthonis, Noordoost-Noord-Brabant, Netherlands
Related Distances from Sint Anthonis
Cesky Tesin, Moravskoslezský kraj, Czechia