Distance from Sint-Genesius-Rode to Aleksandrow Lodzki
The shortest distance (air line) between Sint-Genesius-Rode and Aleksandrow Lodzki is 649.50 mi (1,045.27 km).
How far is Sint-Genesius-Rode from Aleksandrow Lodzki
Sint-Genesius-Rode is located in Arr. Halle-Vilvoorde, Belgium within 50° 44' 42" N 4° 20' 47.04" E (50.7450, 4.3464) coordinates. The local time in Sint-Genesius-Rode is 07:50 (21.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 07:50 (21.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 649.50 miles which is equal to 1,045.27 km.
Sint-Genesius-Rode, Arr. Halle-Vilvoorde, Belgium
Related Distances from Sint-Genesius-Rode
Aleksandrow Lodzki, Łódzki, Poland