Distance from Sint-Joost-ten-Node to Austintown
The shortest distance (air line) between Sint-Joost-ten-Node and Austintown is 3,912.16 mi (6,296.02 km).
How far is Sint-Joost-ten-Node from Austintown
Sint-Joost-ten-Node is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 51' 0" N 4° 22' 59.88" E (50.8500, 4.3833) coordinates. The local time in Sint-Joost-ten-Node is 04:49 (06.05.2025)
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 22:49 (05.05.2025)
The calculated flying distance from Austintown to Austintown is 3,912.16 miles which is equal to 6,296.02 km.
Sint-Joost-ten-Node, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium
Related Distances from Sint-Joost-ten-Node
Austintown, Ohio, United States