Distance from Sint-Joost-ten-Node to Waterbury
The shortest distance (air line) between Sint-Joost-ten-Node and Waterbury is 3,584.36 mi (5,768.47 km).
How far is Sint-Joost-ten-Node from Waterbury
Sint-Joost-ten-Node is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 51' 0" N 4° 22' 59.88" E (50.8500, 4.3833) coordinates. The local time in Sint-Joost-ten-Node is 16:33 (22.05.2025)
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 10:33 (22.05.2025)
The calculated flying distance from Waterbury to Waterbury is 3,584.36 miles which is equal to 5,768.47 km.
Sint-Joost-ten-Node, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium
Related Distances from Sint-Joost-ten-Node
Waterbury, Connecticut, United States