Distance from Sint-Katelijne-Waver to Reynoldsburg
The shortest distance (air line) between Sint-Katelijne-Waver and Reynoldsburg is 4,044.09 mi (6,508.33 km).
How far is Sint-Katelijne-Waver from Reynoldsburg
Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 10:05 (16.12.2025)
Reynoldsburg is located in Ohio, United States within 39° 57' 31.68" N -83° 12' 20.52" W (39.9588, -82.7943) coordinates. The local time in Reynoldsburg is 04:05 (16.12.2025)
The calculated flying distance from Reynoldsburg to Reynoldsburg is 4,044.09 miles which is equal to 6,508.33 km.
Sint-Katelijne-Waver, Arr. Mechelen, Belgium
Related Distances from Sint-Katelijne-Waver
Reynoldsburg, Ohio, United States