Distance from Sint-Oedenrode to Aleksandrow Lodzki
The shortest distance (air line) between Sint-Oedenrode and Aleksandrow Lodzki is 592.28 mi (953.18 km).
How far is Sint-Oedenrode from Aleksandrow Lodzki
Sint-Oedenrode is located in Noordoost-Noord-Brabant, Netherlands within 51° 33' 48.96" N 5° 27' 38.88" E (51.5636, 5.4608) coordinates. The local time in Sint-Oedenrode is 11:38 (07.02.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 11:38 (07.02.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 592.28 miles which is equal to 953.18 km.
Sint-Oedenrode, Noordoost-Noord-Brabant, Netherlands
Related Distances from Sint-Oedenrode
Aleksandrow Lodzki, Łódzki, Poland