Distance from Sioux City to Bad Sassendorf
The shortest distance (air line) between Sioux City and Bad Sassendorf is 4,528.03 mi (7,287.16 km).
How far is Sioux City from Bad Sassendorf
Sioux City is located in Iowa, United States within 42° 29' 45.24" N -97° 36' 35.64" W (42.4959, -96.3901) coordinates. The local time in Sioux City is 05:39 (04.03.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 12:39 (04.03.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,528.03 miles which is equal to 7,287.16 km.
Sioux City, Iowa, United States
Related Distances from Sioux City
Bad Sassendorf, Soest, Germany