Distance from Sioux City to Bad Segeberg
The shortest distance (air line) between Sioux City and Bad Segeberg is 4,497.67 mi (7,238.30 km).
How far is Sioux City from Bad Segeberg
Sioux City is located in Iowa, United States within 42° 29' 45.24" N -97° 36' 35.64" W (42.4959, -96.3901) coordinates. The local time in Sioux City is 05:30 (04.03.2025)
Bad Segeberg is located in Segeberg, Germany within 53° 55' 0.12" N 10° 19' 0.12" E (53.9167, 10.3167) coordinates. The local time in Bad Segeberg is 12:30 (04.03.2025)
The calculated flying distance from Bad Segeberg to Bad Segeberg is 4,497.67 miles which is equal to 7,238.30 km.
Sioux City, Iowa, United States
Related Distances from Sioux City
Bad Segeberg, Segeberg, Germany