Distance from Sioux City to Osternienburg
The shortest distance (air line) between Sioux City and Osternienburg is 4,645.72 mi (7,476.56 km).
How far is Sioux City from Osternienburg
Sioux City is located in Iowa, United States within 42° 29' 45.24" N -97° 36' 35.64" W (42.4959, -96.3901) coordinates. The local time in Sioux City is 03:49 (10.03.2025)
Osternienburg is located in Anhalt-Bitterfeld, Germany within 51° 47' 60" N 12° 1' 0.12" E (51.8000, 12.0167) coordinates. The local time in Osternienburg is 10:49 (10.03.2025)
The calculated flying distance from Osternienburg to Osternienburg is 4,645.72 miles which is equal to 7,476.56 km.
Sioux City, Iowa, United States
Related Distances from Sioux City
Osternienburg, Anhalt-Bitterfeld, Germany