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      Distance from Sioux City to Rotenburg an der Fulda

      The shortest distance (air line) between Sioux City and Rotenburg an der Fulda is 4,605.99 mi (7,412.62 km).

      How far is Sioux City from Rotenburg an der Fulda

      Sioux City is located in Iowa, United States within 42° 29' 45.24" N -97° 36' 35.64" W (42.4959, -96.3901) coordinates. The local time in Sioux City is 08:11 (10.03.2025)

      Rotenburg an der Fulda is located in Hersfeld-Rotenburg, Germany within 50° 59' 45.96" N 9° 43' 40.08" E (50.9961, 9.7278) coordinates. The local time in Rotenburg an der Fulda is 15:11 (10.03.2025)

      The calculated flying distance from Rotenburg an der Fulda to Rotenburg an der Fulda is 4,605.99 miles which is equal to 7,412.62 km.

      Sioux City, Iowa, United States

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      Rotenburg an der Fulda, Hersfeld-Rotenburg, Germany

      Related Distances to Rotenburg an der Fulda