Distance from Sioux City to Rothenburg ob der Tauber
The shortest distance (air line) between Sioux City and Rothenburg ob der Tauber is 4,692.94 mi (7,552.55 km).
How far is Sioux City from Rothenburg ob der Tauber
Sioux City is located in Iowa, United States within 42° 29' 45.24" N -97° 36' 35.64" W (42.4959, -96.3901) coordinates. The local time in Sioux City is 08:41 (10.03.2025)
Rothenburg ob der Tauber is located in Ansbach; Landkreis, Germany within 49° 22' 59.88" N 10° 10' 59.88" E (49.3833, 10.1833) coordinates. The local time in Rothenburg ob der Tauber is 15:41 (10.03.2025)
The calculated flying distance from Rothenburg ob der Tauber to Rothenburg ob der Tauber is 4,692.94 miles which is equal to 7,552.55 km.
Sioux City, Iowa, United States
Related Distances from Sioux City
Rothenburg ob der Tauber, Ansbach; Landkreis, Germany