Distance from Sioux Falls to Begijnendijk
The shortest distance (air line) between Sioux Falls and Begijnendijk is 4,395.18 mi (7,073.37 km).
How far is Sioux Falls from Begijnendijk
Sioux Falls is located in South Dakota, United States within 43° 32' 22.56" N -97° 16' 8.04" W (43.5396, -96.7311) coordinates. The local time in Sioux Falls is 17:28 (24.02.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 00:28 (25.02.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,395.18 miles which is equal to 7,073.37 km.
Sioux Falls, South Dakota, United States
Related Distances from Sioux Falls
Begijnendijk, Arr. Leuven, Belgium