Distance from Sioux Falls to Boortmeerbeek
The shortest distance (air line) between Sioux Falls and Boortmeerbeek is 4,389.14 mi (7,063.63 km).
How far is Sioux Falls from Boortmeerbeek
Sioux Falls is located in South Dakota, United States within 43° 32' 22.56" N -97° 16' 8.04" W (43.5396, -96.7311) coordinates. The local time in Sioux Falls is 02:19 (05.06.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 09:19 (05.06.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 4,389.14 miles which is equal to 7,063.63 km.
Sioux Falls, South Dakota, United States
Related Distances from Sioux Falls
Boortmeerbeek, Arr. Leuven, Belgium