Distance from Sioux Falls to Buggenhout
The shortest distance (air line) between Sioux Falls and Buggenhout is 4,375.75 mi (7,042.10 km).
How far is Sioux Falls from Buggenhout
Sioux Falls is located in South Dakota, United States within 43° 32' 22.56" N -97° 16' 8.04" W (43.5396, -96.7311) coordinates. The local time in Sioux Falls is 02:02 (05.06.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 09:02 (05.06.2025)
The calculated flying distance from Buggenhout to Buggenhout is 4,375.75 miles which is equal to 7,042.10 km.
Sioux Falls, South Dakota, United States
Related Distances from Sioux Falls
Buggenhout, Arr. Dendermonde, Belgium