Distance from Sioux Falls to Diepenbeek
The shortest distance (air line) between Sioux Falls and Diepenbeek is 4,421.66 mi (7,115.97 km).
How far is Sioux Falls from Diepenbeek
Sioux Falls is located in South Dakota, United States within 43° 32' 22.56" N -97° 16' 8.04" W (43.5396, -96.7311) coordinates. The local time in Sioux Falls is 21:36 (24.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 04:36 (25.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,421.66 miles which is equal to 7,115.97 km.
Sioux Falls, South Dakota, United States
Related Distances from Sioux Falls
Diepenbeek, Arr. Hasselt, Belgium