Distance from Sioux Falls to Herenthout
The shortest distance (air line) between Sioux Falls and Herenthout is 4,389.03 mi (7,063.46 km).
How far is Sioux Falls from Herenthout
Sioux Falls is located in South Dakota, United States within 43° 32' 22.56" N -97° 16' 8.04" W (43.5396, -96.7311) coordinates. The local time in Sioux Falls is 00:33 (25.02.2025)
Herenthout is located in Arr. Turnhout, Belgium within 51° 8' 60" N 4° 46' 0.12" E (51.1500, 4.7667) coordinates. The local time in Herenthout is 07:33 (25.02.2025)
The calculated flying distance from Herenthout to Herenthout is 4,389.03 miles which is equal to 7,063.46 km.
Sioux Falls, South Dakota, United States
Related Distances from Sioux Falls
Herenthout, Arr. Turnhout, Belgium