Distance from Sioux Falls to Korneuburg
The shortest distance (air line) between Sioux Falls and Korneuburg is 4,904.07 mi (7,892.34 km).
How far is Sioux Falls from Korneuburg
Sioux Falls is located in South Dakota, United States within 43° 32' 22.56" N -97° 16' 8.04" W (43.5396, -96.7311) coordinates. The local time in Sioux Falls is 14:07 (24.02.2025)
Korneuburg is located in Wiener Umland/Nordteil, Austria within 48° 20' 43.08" N 16° 19' 59.16" E (48.3453, 16.3331) coordinates. The local time in Korneuburg is 21:07 (24.02.2025)
The calculated flying distance from Korneuburg to Korneuburg is 4,904.07 miles which is equal to 7,892.34 km.
Sioux Falls, South Dakota, United States
Related Distances from Sioux Falls
Korneuburg, Wiener Umland/Nordteil, Austria