Distance from Snellville to Bad Sassendorf
The shortest distance (air line) between Snellville and Bad Sassendorf is 4,515.75 mi (7,267.40 km).
How far is Snellville from Bad Sassendorf
Snellville is located in Georgia, United States within 33° 51' 22.32" N -85° 59' 46.32" W (33.8562, -84.0038) coordinates. The local time in Snellville is 08:37 (12.03.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 14:37 (12.03.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,515.75 miles which is equal to 7,267.40 km.
Snellville, Georgia, United States
Related Distances from Snellville
Bad Sassendorf, Soest, Germany