Distance from Sokolow Podlaski to San Giustino
The shortest distance (air line) between Sokolow Podlaski and San Giustino is 767.06 mi (1,234.47 km).
How far is Sokolow Podlaski from San Giustino
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 21:18 (20.05.2025)
San Giustino is located in Perugia, Italy within 43° 32' 60" N 12° 10' 59.88" E (43.5500, 12.1833) coordinates. The local time in San Giustino is 21:18 (20.05.2025)
The calculated flying distance from San Giustino to San Giustino is 767.06 miles which is equal to 1,234.47 km.
Sokolow Podlaski, Siedlecki, Poland