Distance from Spanaway to Begijnendijk
The shortest distance (air line) between Spanaway and Begijnendijk is 4,968.70 mi (7,996.35 km).
How far is Spanaway from Begijnendijk
Spanaway is located in Washington, United States within 47° 5' 52.44" N -123° 34' 36.12" W (47.0979, -122.4233) coordinates. The local time in Spanaway is 03:32 (10.04.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 12:32 (10.04.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,968.70 miles which is equal to 7,996.35 km.
Spanaway, Washington, United States
Related Distances from Spanaway
Begijnendijk, Arr. Leuven, Belgium