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      Distance from Spring Lake to Villanueva de la Canada

      The shortest distance (air line) between Spring Lake and Villanueva de la Canada is 3,985.19 mi (6,413.55 km).

      How far is Spring Lake from Villanueva de la Canada

      Spring Lake is located in North Carolina, United States within 35° 11' 3.48" N -79° 0' 13.68" W (35.1843, -78.9962) coordinates. The local time in Spring Lake is 10:36 (25.05.2025)

      Villanueva de la Canada is located in Madrid, Spain within 40° 27' 0" N -4° 1' 0.12" W (40.4500, -3.9833) coordinates. The local time in Villanueva de la Canada is 16:36 (25.05.2025)

      The calculated flying distance from Villanueva de la Canada to Villanueva de la Canada is 3,985.19 miles which is equal to 6,413.55 km.

      Spring Lake, North Carolina, United States

      Related Distances from Spring Lake

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      Spring Lake to Riverside (California)2,172.93 mi (3,497.00 km)
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      Spring Lake to Washington (District of Columbia)279.26 mi (449.43 km)
      Spring Lake to Baltimore (Maryland)313.38 mi (504.33 km)
      Spring Lake to Atlanta (Georgia)324.23 mi (521.80 km)
      Spring Lake to Philadelphia (Pennsylvania)394.58 mi (635.01 km)
      Spring Lake to Brooklyn (New York)467.02 mi (751.60 km)
      Spring Lake to New York (New York)470.23 mi (756.76 km)
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      Villanueva de la Canada, Madrid, Spain

      Related Distances to Villanueva de la Canada