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      Distance from Spring Lake to Villanueva de la Serena

      The shortest distance (air line) between Spring Lake and Villanueva de la Serena is 3,931.57 mi (6,327.25 km).

      How far is Spring Lake from Villanueva de la Serena

      Spring Lake is located in North Carolina, United States within 35° 11' 3.48" N -79° 0' 13.68" W (35.1843, -78.9962) coordinates. The local time in Spring Lake is 18:23 (27.05.2025)

      Villanueva de la Serena is located in Badajoz, Spain within 38° 58' 0.12" N -6° 12' 0" W (38.9667, -5.8000) coordinates. The local time in Villanueva de la Serena is 00:23 (28.05.2025)

      The calculated flying distance from Villanueva de la Serena to Villanueva de la Serena is 3,931.57 miles which is equal to 6,327.25 km.

      Spring Lake, North Carolina, United States

      Related Distances from Spring Lake

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      Spring Lake to Brooklyn (New York)467.02 mi (751.60 km)
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      Villanueva de la Serena, Badajoz, Spain

      Related Distances to Villanueva de la Serena