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      Distance from Springdale to Villanueva de la Canada

      The shortest distance (air line) between Springdale and Villanueva de la Canada is 4,670.07 mi (7,515.75 km).

      How far is Springdale from Villanueva de la Canada

      Springdale is located in Arkansas, United States within 36° 11' 24.36" N -95° 50' 33.36" W (36.1901, -94.1574) coordinates. The local time in Springdale is 04:26 (10.01.2026)

      Villanueva de la Canada is located in Madrid, Spain within 40° 27' 0" N -4° 1' 0.12" W (40.4500, -3.9833) coordinates. The local time in Villanueva de la Canada is 11:26 (10.01.2026)

      The calculated flying distance from Villanueva de la Canada to Villanueva de la Canada is 4,670.07 miles which is equal to 7,515.75 km.

      Springdale, Arkansas, United States

      Related Distances from Springdale

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      Springdale to St. Louis (Missouri)273.18 mi (439.65 km)
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      Villanueva de la Canada, Madrid, Spain

      Related Distances to Villanueva de la Canada