Distance from Springville to San Lazzaro di Savena
The shortest distance (air line) between Springville and San Lazzaro di Savena is 5,603.80 mi (9,018.44 km).
How far is Springville from San Lazzaro di Savena
Springville is located in Utah, United States within 40° 9' 49.68" N -112° 22' 46.2" W (40.1638, -111.6205) coordinates. The local time in Springville is 20:52 (17.05.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 04:52 (18.05.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 5,603.80 miles which is equal to 9,018.44 km.
Springville, Utah, United States
Related Distances from Springville
San Lazzaro di Savena, Bologna, Italy