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      Distance from Springville to Villanueva de la Canada

      The shortest distance (air line) between Springville and Villanueva de la Canada is 5,249.75 mi (8,448.66 km).

      How far is Springville from Villanueva de la Canada

      Springville is located in Utah, United States within 40° 9' 49.68" N -112° 22' 46.2" W (40.1638, -111.6205) coordinates. The local time in Springville is 23:17 (06.01.2026)

      Villanueva de la Canada is located in Madrid, Spain within 40° 27' 0" N -4° 1' 0.12" W (40.4500, -3.9833) coordinates. The local time in Villanueva de la Canada is 07:17 (07.01.2026)

      The calculated flying distance from Villanueva de la Canada to Villanueva de la Canada is 5,249.75 miles which is equal to 8,448.66 km.

      Springville, Utah, United States

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      Villanueva de la Canada, Madrid, Spain

      Related Distances to Villanueva de la Canada