Distance from Sredisce ob Dravi to Jacksonville Beach
The shortest distance (air line) between Sredisce ob Dravi and Jacksonville Beach is 5,072.14 mi (8,162.82 km).
How far is Sredisce ob Dravi from Jacksonville Beach
Sredisce ob Dravi is located in Podravska, Slovenia within 46° 23' 35.88" N 16° 16' 19.92" E (46.3933, 16.2722) coordinates. The local time in Sredisce ob Dravi is 16:33 (25.12.2025)
Jacksonville Beach is located in Florida, United States within 30° 16' 41.52" N -82° 35' 43.8" W (30.2782, -81.4045) coordinates. The local time in Jacksonville Beach is 10:33 (25.12.2025)
The calculated flying distance from Jacksonville Beach to Jacksonville Beach is 5,072.14 miles which is equal to 8,162.82 km.
Sredisce ob Dravi, Podravska, Slovenia
Related Distances from Sredisce ob Dravi
Jacksonville Beach, Florida, United States