Distance from Steenokkerzeel to Florida Ridge
The shortest distance (air line) between Steenokkerzeel and Florida Ridge is 4,549.73 mi (7,322.09 km).
How far is Steenokkerzeel from Florida Ridge
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 11:19 (09.12.2025)
Florida Ridge is located in Florida, United States within 27° 34' 49.8" N -81° 36' 54.72" W (27.5805, -80.3848) coordinates. The local time in Florida Ridge is 05:19 (09.12.2025)
The calculated flying distance from Florida Ridge to Florida Ridge is 4,549.73 miles which is equal to 7,322.09 km.
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium
Related Distances from Steenokkerzeel
Florida Ridge, Florida, United States