Distance from Steenokkerzeel to Franklin Lakes
The shortest distance (air line) between Steenokkerzeel and Franklin Lakes is 3,658.86 mi (5,888.37 km).
How far is Steenokkerzeel from Franklin Lakes
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 21:24 (09.12.2025)
Franklin Lakes is located in New Jersey, United States within 41° 0' 30.96" N -75° 47' 30.12" W (41.0086, -74.2083) coordinates. The local time in Franklin Lakes is 15:24 (09.12.2025)
The calculated flying distance from Franklin Lakes to Franklin Lakes is 3,658.86 miles which is equal to 5,888.37 km.
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium
Related Distances from Steenokkerzeel
Franklin Lakes, New Jersey, United States