Distance from Steenokkerzeel to Huntington Park
The shortest distance (air line) between Steenokkerzeel and Huntington Park is 5,617.37 mi (9,040.28 km).
How far is Steenokkerzeel from Huntington Park
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 21:08 (16.12.2025)
Huntington Park is located in California, United States within 33° 58' 48" N -119° 46' 59.88" W (33.9800, -118.2167) coordinates. The local time in Huntington Park is 12:08 (16.12.2025)
The calculated flying distance from Huntington Park to Huntington Park is 5,617.37 miles which is equal to 9,040.28 km.
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium
Related Distances from Steenokkerzeel
Huntington Park, California, United States