Distance from Steenokkerzeel to Jamestown
The shortest distance (air line) between Steenokkerzeel and Jamestown is 3,810.82 mi (6,132.92 km).
How far is Steenokkerzeel from Jamestown
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 13:50 (08.01.2026)
Jamestown is located in New York, United States within 42° 5' 51.36" N -80° 45' 47.88" W (42.0976, -79.2367) coordinates. The local time in Jamestown is 07:50 (08.01.2026)
The calculated flying distance from Jamestown to Jamestown is 3,810.82 miles which is equal to 6,132.92 km.
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium
Related Distances from Steenokkerzeel
Jamestown, New York, United States