Distance from Steenokkerzeel to Jefferson Hills
The shortest distance (air line) between Steenokkerzeel and Jefferson Hills is 3,919.71 mi (6,308.16 km).
How far is Steenokkerzeel from Jefferson Hills
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 15:07 (08.01.2026)
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 09:07 (08.01.2026)
The calculated flying distance from Jefferson Hills to Jefferson Hills is 3,919.71 miles which is equal to 6,308.16 km.
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium
Related Distances from Steenokkerzeel
Jefferson Hills, Pennsylvania, United States