Distance from Steenokkerzeel to Jefferson Valley-Yorktown
The shortest distance (air line) between Steenokkerzeel and Jefferson Valley-Yorktown is 3,628.93 mi (5,840.20 km).
How far is Steenokkerzeel from Jefferson Valley-Yorktown
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 23:34 (05.01.2026)
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 17:34 (05.01.2026)
The calculated flying distance from Jefferson Valley-Yorktown to Jefferson Valley-Yorktown is 3,628.93 miles which is equal to 5,840.20 km.
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium
Related Distances from Steenokkerzeel
Jefferson Valley-Yorktown, New York, United States