Distance from Steubenville to Begijnendijk
The shortest distance (air line) between Steubenville and Begijnendijk is 3,952.70 mi (6,361.25 km).
How far is Steubenville from Begijnendijk
Steubenville is located in Ohio, United States within 40° 21' 55.08" N -81° 20' 53.16" W (40.3653, -80.6519) coordinates. The local time in Steubenville is 01:36 (25.02.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 07:36 (25.02.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,952.70 miles which is equal to 6,361.25 km.
Steubenville, Ohio, United States
Related Distances from Steubenville
Begijnendijk, Arr. Leuven, Belgium