Distance from Stevenage to Aleksandrow Lodzki
The shortest distance (air line) between Stevenage and Aleksandrow Lodzki is 829.85 mi (1,335.51 km).
How far is Stevenage from Aleksandrow Lodzki
Stevenage is located in Hertfordshire, United Kingdom within 51° 54' 6.12" N -1° 47' 53.16" W (51.9017, -0.2019) coordinates. The local time in Stevenage is 02:29 (24.02.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 03:29 (24.02.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 829.85 miles which is equal to 1,335.51 km.
Stevenage, Hertfordshire, United Kingdom
Related Distances from Stevenage
Aleksandrow Lodzki, Łódzki, Poland