Distance from Stevenage to Secaucus
The shortest distance (air line) between Stevenage and Secaucus is 3,449.12 mi (5,550.82 km).
How far is Stevenage from Secaucus
Stevenage is located in Hertfordshire, United Kingdom within 51° 54' 6.12" N -1° 47' 53.16" W (51.9017, -0.2019) coordinates. The local time in Stevenage is 12:22 (05.10.2025)
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 07:22 (05.10.2025)
The calculated flying distance from Secaucus to Secaucus is 3,449.12 miles which is equal to 5,550.82 km.
Stevenage, Hertfordshire, United Kingdom
Related Distances from Stevenage
Secaucus, New Jersey, United States