Distance from Strongsville to Begijnendijk
The shortest distance (air line) between Strongsville and Begijnendijk is 3,955.14 mi (6,365.18 km).
How far is Strongsville from Begijnendijk
Strongsville is located in Ohio, United States within 41° 18' 46.08" N -82° 10' 7.32" W (41.3128, -81.8313) coordinates. The local time in Strongsville is 11:17 (04.04.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 17:17 (04.04.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,955.14 miles which is equal to 6,365.18 km.
Strongsville, Ohio, United States
Related Distances from Strongsville
Begijnendijk, Arr. Leuven, Belgium