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      Distance from Strongsville to Sint-Pieters-Leeuw

      The shortest distance (air line) between Strongsville and Sint-Pieters-Leeuw is 3,941.67 mi (6,343.51 km).

      How far is Strongsville from Sint-Pieters-Leeuw

      Strongsville is located in Ohio, United States within 41° 18' 46.08" N -82° 10' 7.32" W (41.3128, -81.8313) coordinates. The local time in Strongsville is 11:29 (07.04.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 17:29 (07.04.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 3,941.67 miles which is equal to 6,343.51 km.

      Strongsville, Ohio, United States

      Related Distances from Strongsville

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      Strongsville to Riverside (California)1,996.58 mi (3,213.19 km)
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      Strongsville to Washington (District of Columbia)303.94 mi (489.15 km)
      Strongsville to Chicago (Illinois)304.75 mi (490.45 km)
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      Strongsville to Philadelphia (Pennsylvania)362.32 mi (583.10 km)
      Strongsville to Brooklyn (New York)413.51 mi (665.47 km)
      Strongsville to New York (New York)414.32 mi (666.79 km)
      Strongsville to Queens (New York)420.37 mi (676.52 km)
      Strongsville to St. Louis (Missouri)482.10 mi (775.86 km)
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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw