Distance from Summerfield to Sveti Ivan Zelina
The shortest distance (air line) between Summerfield and Sveti Ivan Zelina is 4,493.35 mi (7,231.35 km).
How far is Summerfield from Sveti Ivan Zelina
Summerfield is located in Maryland, United States within 38° 54' 15.12" N -77° 7' 55.92" W (38.9042, -76.8678) coordinates. The local time in Summerfield is 05:20 (05.06.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 11:20 (05.06.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,493.35 miles which is equal to 7,231.35 km.
Summerfield, Maryland, United States
Related Distances from Summerfield
Sveti Ivan Zelina, Zagrebačka županija, Croatia