Distance from Summerlin South to Savigny-le-Temple
The shortest distance (air line) between Summerlin South and Savigny-le-Temple is 5,453.77 mi (8,776.99 km).
How far is Summerlin South from Savigny-le-Temple
Summerlin South is located in Nevada, United States within 36° 7' 27.12" N -116° 40' 3.36" W (36.1242, -115.3324) coordinates. The local time in Summerlin South is 14:39 (03.03.2025)
Savigny-le-Temple is located in Seine-et-Marne, France within 48° 35' 2.76" N 2° 34' 59.52" E (48.5841, 2.5832) coordinates. The local time in Savigny-le-Temple is 23:39 (03.03.2025)
The calculated flying distance from Savigny-le-Temple to Savigny-le-Temple is 5,453.77 miles which is equal to 8,776.99 km.
Summerlin South, Nevada, United States
Related Distances from Summerlin South
Savigny-le-Temple, Seine-et-Marne, France