Distance from Summerville to Begijnendijk
The shortest distance (air line) between Summerville and Begijnendijk is 4,282.78 mi (6,892.46 km).
How far is Summerville from Begijnendijk
Summerville is located in South Carolina, United States within 33° 0' 5.76" N -81° 49' 12.36" W (33.0016, -80.1799) coordinates. The local time in Summerville is 21:38 (04.04.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 03:38 (05.04.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,282.78 miles which is equal to 6,892.46 km.
Summerville, South Carolina, United States
Related Distances from Summerville
Begijnendijk, Arr. Leuven, Belgium