Distance from Summerville to Lyaskovets
The shortest distance (air line) between Summerville and Lyaskovets is 5,403.37 mi (8,695.88 km).
How far is Summerville from Lyaskovets
Summerville is located in South Carolina, United States within 33° 0' 5.76" N -81° 49' 12.36" W (33.0016, -80.1799) coordinates. The local time in Summerville is 20:55 (07.04.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 03:55 (08.04.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 5,403.37 miles which is equal to 8,695.88 km.
Summerville, South Carolina, United States
Related Distances from Summerville
Lyaskovets, Veliko Tarnovo, Bulgaria