Distance from Superior to Aleksandrow Kujawski
The shortest distance (air line) between Superior and Aleksandrow Kujawski is 4,443.89 mi (7,151.75 km).
How far is Superior from Aleksandrow Kujawski
Superior is located in Wisconsin, United States within 46° 41' 38.76" N -93° 55' 3.72" W (46.6941, -92.0823) coordinates. The local time in Superior is 14:00 (13.01.2026)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 21:00 (13.01.2026)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,443.89 miles which is equal to 7,151.75 km.
Superior, Wisconsin, United States
Related Distances from Superior
Aleksandrow Kujawski, Włocławski, Poland