Distance from Tahlequah to Jefferson Valley-Yorktown
The shortest distance (air line) between Tahlequah and Jefferson Valley-Yorktown is 1,199.12 mi (1,929.79 km).
How far is Tahlequah from Jefferson Valley-Yorktown
Tahlequah is located in Oklahoma, United States within 35° 54' 40.32" N -95° 1' 22.8" W (35.9112, -94.9770) coordinates. The local time in Tahlequah is 10:15 (17.12.2025)
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 11:15 (17.12.2025)
The calculated flying distance from Jefferson Valley-Yorktown to Jefferson Valley-Yorktown is 1,199.12 miles which is equal to 1,929.79 km.
Tahlequah, Oklahoma, United States
Related Distances from Tahlequah
Jefferson Valley-Yorktown, New York, United States