Distance from Tahlequah to Petersburg
The shortest distance (air line) between Tahlequah and Petersburg is 978.67 mi (1,575.01 km).
How far is Tahlequah from Petersburg
Tahlequah is located in Oklahoma, United States within 35° 54' 40.32" N -95° 1' 22.8" W (35.9112, -94.9770) coordinates. The local time in Tahlequah is 14:51 (19.12.2025)
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 15:51 (19.12.2025)
The calculated flying distance from Petersburg to Petersburg is 978.67 miles which is equal to 1,575.01 km.
Tahlequah, Oklahoma, United States
Related Distances from Tahlequah
Petersburg, Virginia, United States