Distance from Tahlequah to Roosevelt
The shortest distance (air line) between Tahlequah and Roosevelt is 1,202.52 mi (1,935.27 km).
How far is Tahlequah from Roosevelt
Tahlequah is located in Oklahoma, United States within 35° 54' 40.32" N -95° 1' 22.8" W (35.9112, -94.9770) coordinates. The local time in Tahlequah is 15:56 (20.12.2025)
Roosevelt is located in New York, United States within 40° 40' 46.92" N -74° 24' 58.68" W (40.6797, -73.5837) coordinates. The local time in Roosevelt is 16:56 (20.12.2025)
The calculated flying distance from Roosevelt to Roosevelt is 1,202.52 miles which is equal to 1,935.27 km.
Tahlequah, Oklahoma, United States
Related Distances from Tahlequah
Roosevelt, New York, United States