Distance from Tanaina to Aleksandrow Kujawski
The shortest distance (air line) between Tanaina and Aleksandrow Kujawski is 4,496.49 mi (7,236.41 km).
How far is Tanaina from Aleksandrow Kujawski
Tanaina is located in Alaska, United States within 61° 39' 27.36" N -150° 34' 25.32" W (61.6576, -149.4263) coordinates. The local time in Tanaina is 09:31 (08.01.2026)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 19:31 (08.01.2026)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,496.49 miles which is equal to 7,236.41 km.
Tanaina, Alaska, United States
Related Distances from Tanaina
Aleksandrow Kujawski, Włocławski, Poland