Distance from Targu Secuiesc to Aleksandrow Kujawski
The shortest distance (air line) between Targu Secuiesc and Aleksandrow Kujawski is 580.63 mi (934.44 km).
How far is Targu Secuiesc from Aleksandrow Kujawski
Targu Secuiesc is located in Covasna, Romania within 45° 59' 48.84" N 26° 8' 26.16" E (45.9969, 26.1406) coordinates. The local time in Targu Secuiesc is 05:54 (17.05.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 04:54 (17.05.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 580.63 miles which is equal to 934.44 km.
Targu Secuiesc, Covasna, Romania
Related Distances from Targu Secuiesc
Aleksandrow Kujawski, Włocławski, Poland