Distance from Targu Secuiesc to Bartlesville
The shortest distance (air line) between Targu Secuiesc and Bartlesville is 5,684.29 mi (9,147.97 km).
How far is Targu Secuiesc from Bartlesville
Targu Secuiesc is located in Covasna, Romania within 45° 59' 48.84" N 26° 8' 26.16" E (45.9969, 26.1406) coordinates. The local time in Targu Secuiesc is 20:15 (20.12.2025)
Bartlesville is located in Oklahoma, United States within 36° 44' 11.4" N -96° 3' 15.84" W (36.7365, -95.9456) coordinates. The local time in Bartlesville is 12:15 (20.12.2025)
The calculated flying distance from Bartlesville to Bartlesville is 5,684.29 miles which is equal to 9,147.97 km.
Targu Secuiesc, Covasna, Romania
Related Distances from Targu Secuiesc
Bartlesville, Oklahoma, United States